解释结构模型快速排序层级分析
此处输入要素的个数:
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 |
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第一步:生成自乘矩阵
系统的邻接矩阵的表示
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子 | 丑 | 寅 | 卯 | 辰 | 巳 | 午 | 未 | 申 | 酉 | 戌 | 亥 | 乾 | 坤 | 震 | 巽 | 坎 | 离 | 艮 | 兑 |
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第二步:对系统进行环路分析,并获得一个获得一个新序
0=>丑
1=>子
2=>寅
3=>卯
4=>辰
5=>巳
6=>戌
7=>离
8=>午
9=>未
10=>亥
11=>申
12=>酉
13=>乾
14=>坤
15=>震
16=>巽
17=>坎
18=>艮
19=>兑
第三步:根据环路与新序,进行矩阵缩减
分析的矩阵为:
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丑 | 子 | 寅 | 卯 | 辰 | 巳 | 戌 | 离 | 午 | 未 | 亥 | 申 | 酉 | 乾 | 坤 | 震 | 巽 | 坎 | 艮 | 兑 |
| 丑 |
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卯、 |
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戌、 |
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离、 |
| 未 |
寅、巳、 |
| 亥 |
子、午、 |
| 申 |
未、亥、 |
| 酉 |
丑、子、未、亥、 |
| 坤 |
巳、 |
| 震 |
丑、坤、 |
| 巽 |
离、 |
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卯、 |
| 艮 |
未、亥、 |
第四步:对无环矩阵进行缩边,也就是去掉所有的向前边!
可达矩阵:
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丑 | 子 | 寅 | 卯 | 辰 | 巳 | 戌 | 离 | 午 | 未 | 亥 | 申 | 酉 | 乾 | 坤 | 震 | 巽 | 坎 | 艮 | 兑 |
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骨架矩阵
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| 子 |
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子、 |
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卯、 |
| 戌 |
子、 |
| 离 |
戌、 |
| 午 |
离、 |
| 未 |
寅、巳、 |
| 亥 |
午、 |
| 申 |
未、亥、 |
| 酉 |
未、亥、 |
| 坤 |
巳、 |
| 震 |
丑、坤、 |
| 巽 |
离、 |
| 坎 |
卯、 |
| 艮 |
未、亥、 |
第五步:对一般性骨架矩阵进行层级分解,可以是原因优先,可以是结果优先
原因优先层级划分最终图形
结果优先层级划分最终图形
弹性势能最大,两端发散的的层级结果
弹性势能最小,中间靠拢的结果
第六步:对一般性骨架矩阵的中的活动要素进行分析
| 层级的序号 | 原因优先的方法-得到的各层级的要素 | 结果优先的方法-得到的各层级要素 | 共同有的要素 | 活动的要素 |
| 1 | 丑 | 丑,卯,辰,乾,兑 | 丑 | 卯,辰,乾,兑 |
| 2 | 子 | 子,巳,坎 | 子 | 巳,坎 |
| 3 | 戌 | 寅,戌,坤 | 戌 | 寅,坤 |
| 4 | 卯,离 | 离,未,震 | 离 | 卯,未,震 |
| 5 | 寅,巳,午 | 午,巽 | 午 | 寅,巳,巽 |
| 6 | 未,亥,坤 | 亥 | 亥 | 未,坤 |
| 7 | 辰,申,酉,乾,震,巽,坎,艮,兑 | 申,酉,艮 | 申,酉,艮 | 辰,乾,震,巽,坎,兑 |
由上表计算得出活动的要素以及它们活动的层级:
| 要素的序号 | 要素的名称 | 要素的标题 | 开始层级 | 终止层级 |
| 3 | 卯 | 卯 | 1 | 4 |
| 4 | 辰 | 辰 | 1 | 7 |
| 13 | 乾 | 乾 | 1 | 7 |
| 19 | 兑 | 兑 | 1 | 7 |
| 5 | 巳 | 巳 | 2 | 5 |
| 17 | 坎 | 坎 | 2 | 7 |
| 2 | 寅 | 寅 | 3 | 5 |
| 14 | 坤 | 坤 | 3 | 6 |
| 9 | 未 | 未 | 4 | 6 |
| 15 | 震 | 震 | 4 | 7 |
| 16 | 巽 | 巽 | 5 | 7 |
找到活动要素,并在层级中移动这些活动要素找出最好的结果。活动的要素要注意本身有因果关系的
A、分层的结果一定要符合箭头一定向上
B、不能增加层级的数目
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